Please login with a confirmed email address before reporting spam
Posted:
6 years ago
10.05.2019, 08:27 GMT-4
Updated:
6 years ago
10.05.2019, 08:28 GMT-4
I am not familiar with the fluid flow modules, but in the moving wall
condition, is it not possible to specify a vector expression for the wall's velocity?
If the above is possible, then you could input the local instaneous velocity as a function of spatial coordinates. So for a point
such that
is equal to the inner cylinder's radius, I would expect this velocity assuming a constant pulsation 




where the sign of
determines whether the rotation is clockwise or counter-clockwise.
Note that I assumed that the axis
is both the axis of symmetry and the axis of rotation of the inner cylinder. You have to tinker a little bit if your origin is different.
I am not familiar with the fluid flow modules, but in the `moving wall` condition, is it not possible to specify a vector expression for the wall's velocity?
If the above is possible, then you could input the local instaneous velocity as a function of spatial coordinates. So for a point P=(x_P, y_P, z_P) = (r_P, \theta_P, z_P) such that r_P is equal to the inner cylinder's radius, I would expect this velocity assuming a constant pulsation \omega
||\vec v|| = r_P |\omega|
v_x = \sin(\theta_P) \cdot r_P \cdot \omega
v_y = - \cos(\theta_P) \cdot r_P \cdot \omega
v_z = 0
where the sign of \omega determines whether the rotation is clockwise or counter-clockwise.
Note that I assumed that the axis (x, y, z) = (0, 0, z) is both the axis of symmetry and the axis of rotation of the inner cylinder. You have to tinker a little bit if your origin is different.
Please login with a confirmed email address before reporting spam
Posted:
6 years ago
10.05.2019, 08:29 GMT-4
Actually, I just realized that the pulsation ω needs not to be constant for this to work.
Actually, I just realized that the pulsation ω needs not to be constant for this to work.