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Best way to define the characteristic/indicator function of a square?

Posted 30.04.2019, 03:54 GMT-4 Parameters, Variables, & Functions 1 Reply

Adel Moreno
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Hi,

I was wondering if there is not a better way (shorter) to define a characteristic/indicator function of a square/cube than with the function "flc1hs". Indeed, when I use flc1hs (or one of his declination i.e flc2hs) in 2d or 3d and for my specific problem, I got a lot of these functions.

Example in 2d : Let's say that we want to implement the indicator function of , I write flc1hs(x-0.2,0.01)* flc1hs(0.4-x,0.01)* flc1hs(y,0.01)* flc1hs(0.2-y,0.01).

Thanks

1 Reply Last Post 08.05.2019, 17:06 GMT-4
Alexis Prel
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Posted: 6 years ago 08.05.2019, 17:06 GMT-4

I have not tested it, but doesn't this achieve the same result?

flc1hs( (x-x_a)*(x_b-x)*(y-y_a)*(y_b-y), d)

for with a smoothing scale

I have not tested it, but doesn't this achieve the same result? flc1hs( (x-x_a)*(x_b-x)*(y-y_a)*(y_b-y), d) for x \in [x_a, x_b] ; y \in [y_a, y_b] with a smoothing scale d

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