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Posted:
1 decade ago
14.07.2010, 09:17 GMT-4
Who can help how can Comsol be used for modeling of ferroelectrics below Curie point.
Who can help how can Comsol be used for modeling of ferroelectrics below Curie point.
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Posted:
1 decade ago
14.07.2010, 11:05 GMT-4
Using a step function in material properties (temperature depending magnetic permeability)? But, I've never used the ACDC-Module. Is it coupled with heat transfer (-> e.g. T_htgh)?
mu=flc1hs(T_htgh-T_curie,0.5)*mu_ferro
Using a step function in material properties (temperature depending magnetic permeability)? But, I've never used the ACDC-Module. Is it coupled with heat transfer (-> e.g. T_htgh)?
mu=flc1hs(T_htgh-T_curie,0.5)*mu_ferro
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Posted:
1 decade ago
14.07.2010, 12:21 GMT-4
I want to obtain the distribution of spontaneous polarization and electrical potantial which appear in ferroelectrics below Curie point. I'm modeling a composition material consisting of dielectric matrix and ferroelectrics grains. The polarization and potential submit partial differential system below Curie point. This partial differential system is non-linear and has following view:
æ•?? + ?•? - ?•?^3 = d?/dz-E0
?•?? = 4?•dP/dz
I want to obtain the distribution of spontaneous polarization and electrical potantial which appear in ferroelectrics below Curie point. I'm modeling a composition material consisting of dielectric matrix and ferroelectrics grains. The polarization and potential submit partial differential system below Curie point. This partial differential system is non-linear and has following view:
æ•?? + ?•? - ?•?^3 = d?/dz-E0
?•?? = 4?•dP/dz
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Posted:
1 decade ago
14.07.2010, 12:30 GMT-4
æ•div(gradP) + a•P - b•P^3 = dFi/dz-E0
epsilon•div(gradFi) = 4pi•dP/dz
æ•div(gradP) + a•P - b•P^3 = dFi/dz-E0
epsilon•div(gradFi) = 4pi•dP/dz