Hello Emran Khander
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Posted:
1 decade ago
02.05.2013, 06:05 GMT-4
Dear Emeran
i hope that you are well, i want to simulate the dispersion curve in comsol by changing the acoustic freq., so please if you have idea for which Eq. i must you to draw the curve between the K and Freq. ?
Best regards
Dear Emeran
i hope that you are well, i want to simulate the dispersion curve in comsol by changing the acoustic freq., so please if you have idea for which Eq. i must you to draw the curve between the K and Freq. ?
Best regards
Please login with a confirmed email address before reporting spam
Posted:
1 decade ago
02.05.2013, 09:42 GMT-4
Hi Emran,
I believe matlab does not have an easy way to derivate as (for example) Mathematica does.
The reason is that numerical derivation is not a trivial subject.
As a first approach you can use the polyfit function in matlab and then derivating the output order-m polynomial is a trivial task. But beware! this is only accurate if your interpolated data behaves as a polynomial of order m.
Recently, I had to implement the Richardson's method to find the group dispersion (second derivate) for very low values in a very noisy function. I found this method very accurate and easy to implement. Check Numerical Recipes (
www.nr.com) and look for the dfridr function that explains the mentioned algorithm.
cheers,
--
Felipe BM
Hi Emran,
I believe matlab does not have an easy way to derivate as (for example) Mathematica does.
The reason is that numerical derivation is not a trivial subject.
As a first approach you can use the polyfit function in matlab and then derivating the output order-m polynomial is a trivial task. But beware! this is only accurate if your interpolated data behaves as a polynomial of order m.
Recently, I had to implement the Richardson's method to find the group dispersion (second derivate) for very low values in a very noisy function. I found this method very accurate and easy to implement. Check Numerical Recipes (www.nr.com) and look for the dfridr function that explains the mentioned algorithm.
cheers,
--
Felipe BM