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Lumped port incident power

Posted 10.11.2020, 07:17 GMT-5 1 Reply

Azeem Imtiaz
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Hi Richard,

when using the coaxial catagory in lumped port implementation, we input voltage to the port. can you please help me in calculating how much power is incident upon the port in terms of watts? for eaxmple when I use 250V, how much power would it relate to?

Best regards, Azeem

1 Reply Last Post 10.11.2020, 20:58 GMT-5
Robert Koslover Certified Consultant
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Posted: 4 years ago 10.11.2020, 20:58 GMT-5
Updated: 4 years ago 10.11.2020, 21:00 GMT-5

First, I'll assume you are doing an RF model in frequency-domain mode. You may also notice that you had to specify a characteristic reference impedance. The default is 50 ohms. Bear in mind that the voltage you are specifying is the peak voltage, not rms. So the power becomes . Note that if you have an impedance mismatch (which is very likely, if you don't put in effort to choose the reference Z to match), then your actual forward power will be less.

250 V into 50 ohms would thus be 625 Watts.

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Scientific Applications & Research Associates (SARA) Inc.
www.comsol.com/partners-consultants/certified-consultants/sara
First, I'll *assume* you are doing an RF model in frequency-domain mode. You may also notice that you had to specify a characteristic reference impedance. The default is 50 ohms. Bear in mind that the voltage you are specifying is the *peak* voltage, not rms. So the power becomes V^2/(2*Z_r_e_f). Note that if you have an impedance mismatch (which is very likely, if you don't put in effort to choose the reference Z to match), then your actual forward power will be less. 250 V into 50 ohms would thus be 625 Watts.

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