Edgar J. Kaiser
Certified Consultant
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Posted:
4 years ago
06.07.2020, 13:04 GMT-4
Mark,
just a little thought. You apply a symmetry plane and a perpendicular antisymmetry plane. This cannot be correct for the coil.
Cheers
Edgar
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Mark,
just a little thought. You apply a symmetry plane and a perpendicular antisymmetry plane. This cannot be correct for the coil.
Cheers
Edgar
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Posted:
4 years ago
07.07.2020, 05:32 GMT-4
Hi Edgar,
Of course, I was thinking in terms of the permanent magnet. I believe the coil (as you state) requires 2 antisymmetric planes, but the permanent magnet structure requires one plane (the xz plane) to be symmetric, yet the other (yz) plane to be antisymmetric.
Can 1/4 symmetry still be used? Is there some workaround that can be utilised? the actual geometry I am using is hitting the RAM limit of my machine, hence my desire to use a second symmetry plane if possible.
Thanks in advance for any feedback...
Mark
Hi Edgar,
Of course, I was thinking in terms of the permanent magnet. I believe the coil (as you state) requires 2 antisymmetric planes, but the permanent magnet structure requires one plane (the xz plane) to be symmetric, yet the other (yz) plane to be antisymmetric.
Can 1/4 symmetry still be used? Is there some workaround that can be utilised? the actual geometry I am using is hitting the RAM limit of my machine, hence my desire to use a second symmetry plane if possible.
Thanks in advance for any feedback...
Mark
Edgar J. Kaiser
Certified Consultant
Please login with a confirmed email address before reporting spam
Posted:
4 years ago
07.07.2020, 06:25 GMT-4
Hi Mark,
any symmetry you want to use must be respected by the whole model, the complete geometry, all fields and all boundary conditions. So I think you can only use the first plane.
Cheers
Edgar
-------------------
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
Hi Mark,
any symmetry you want to use must be respected by the whole model, the complete geometry, all fields and all boundary conditions. So I think you can only use the first plane.
Cheers
Edgar
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Posted:
4 years ago
07.07.2020, 06:29 GMT-4
Hi Edgar,
I thought that was going to be the case... I think I was asking more out of hope than expecatation!
Thanks again for your confirmation... time to buy some more RAM!
Hi Edgar,
I thought that was going to be the case... I think I was asking more out of hope than expecatation!
Thanks again for your confirmation... time to buy some more RAM!
Durk de Vries
COMSOL Employee
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Posted:
4 years ago
09.07.2020, 09:45 GMT-4
Updated:
4 years ago
09.07.2020, 09:48 GMT-4
Hi Mark,
The forces are computed by integrating the Maxwell surface stress tensor. Please consider adding fillets to your magnet, before investigating forces. Without the fillets, your Maxwell surface stress tensor with develop singularities at the (infinitely) sharp edges of your magnet. This will greatly reduce the accuracy of your force calculation. For the nonmagnetic copper coil, you could consider a domain integral of the Lorentz force instead.
More on fillets can be seen here: https://www.comsol.com/blogs/fillet-away-your-electromagnetic-field-singularities/
For the Lorentz force: https://www.comsol.com/model/electromagnetic-forces-on-parallel-current-carrying-wires-131
When it comes to forces normal to the symmetry plane: The integral is done over the geometry you have in your model, without considering symmetry. In reality, one half of your coil will pull in one direction, the other half will pull in the other direction, and if there is symmetry, the sum of both will amount to zero. If you integrate only over half your coil because the other half is not in your model, you will get a nonzero value.
Once you are aware of this behavior, you can compensate for it: If you are integrating over half a magnet or half a coil and you know there should be an equal and opposite-pulling counterpart on the other side of your symmetry plane, you can consider the force normal to your symmetry plane to be zero.
However, if your magnet does not cross the symmetry plane, but is oriented along the symmetry plane, it means you have an identical magnet on the other side and both magnets will repel each other (in case of a magnetic insulation boundary condition). If the symmetry plane is a perfect magnetic conductor, they will attract each other. In that case, there is actually a total net. force on each individual magnet. But the sum of the forces of both magnets is still zero.
You can even reason the other way around: If you could hypothetically cut a magnet in half, creating two monopoles (which has not yet been proven possible by science, but you CAN model it if you like), you will see the two poles attract each other (like positive and negative electrical charges).
So the poles of a magnet pull on each other. The main reason you would expect a value of zero, is because you typically consider the force on the entire magnet, not just on one of its poles.
We have a resource combing symmetry conditions, magnets, force calculations and fillets. It is located here: https://www.comsol.com/model/electromagnetic-force-verification-series-55871
For further questions related to your modeling, feel free to contact our Support team.
Online Support Center: https://www.comsol.com/support
Email: support@comsol.com
Hi Mark,
The forces are computed by integrating the Maxwell surface stress tensor. Please consider adding fillets to your magnet, before investigating forces. Without the fillets, your Maxwell surface stress tensor with develop singularities at the (infinitely) sharp edges of your magnet. This will greatly reduce the accuracy of your force calculation. For the nonmagnetic copper coil, you could consider a domain integral of the Lorentz force instead.
More on fillets can be seen here: [https://www.comsol.com/blogs/fillet-away-your-electromagnetic-field-singularities/](https://www.comsol.com/blogs/fillet-away-your-electromagnetic-field-singularities/)
For the Lorentz force: [https://www.comsol.com/model/electromagnetic-forces-on-parallel-current-carrying-wires-131](https://www.comsol.com/model/electromagnetic-forces-on-parallel-current-carrying-wires-131)
When it comes to forces normal to the symmetry plane: The integral is done over the geometry you have in your model, without considering symmetry. In reality, one half of your coil will pull in one direction, the other half will pull in the other direction, and if there is symmetry, the sum of both will amount to zero. If you integrate only over half your coil because the other half is not in your model, you will get a nonzero value.
Once you are aware of this behavior, you can compensate for it: If you are integrating over half a magnet or half a coil and you know there should be an equal and opposite-pulling counterpart on the other side of your symmetry plane, you can consider the force normal to your symmetry plane to be zero.
However, if your magnet does not cross the symmetry plane, but is oriented along the symmetry plane, it means you have an identical magnet on the other side and both magnets will repel each other (in case of a magnetic insulation boundary condition). If the symmetry plane is a perfect magnetic conductor, they will attract each other. In that case, there is actually a total net. force on each individual magnet. But the sum of the forces of both magnets is still zero.
You can even reason the other way around: If you could hypothetically cut a magnet in half, creating two monopoles (*which has not yet been proven possible by science, but you CAN model it if you like*), you will see the two poles attract each other (like positive and negative electrical charges).
So the poles of a magnet pull on each other. The main reason you would expect a value of zero, is because you typically consider the force on the entire magnet, not just on one of its poles.
We have a resource combing symmetry conditions, magnets, force calculations and fillets. It is located here: [https://www.comsol.com/model/electromagnetic-force-verification-series-55871](https://www.comsol.com/model/electromagnetic-force-verification-series-55871)
For further questions related to your modeling, feel free to contact our Support team.
Online Support Center: [https://www.comsol.com/support](https://www.comsol.com/support)
Email: [support@comsol.com](mailto:support@comsol.com)