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Posted:
1 decade ago
09.11.2011, 09:40 GMT-5
Hi,
to my knowledge it is not possible. But even if it was possible, it doesn't make a difference. If the domain is a conductor, it will be at the potential of the boundary as a whole.
Cheers
Edgar
Hi,
to my knowledge it is not possible. But even if it was possible, it doesn't make a difference. If the domain is a conductor, it will be at the potential of the boundary as a whole.
Cheers
Edgar
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Posted:
1 decade ago
09.11.2011, 11:20 GMT-5
thanks edgar.
i know that dosn´t make a difference. i asked because i am working with Matlab Livelink. so it is more practical for me to use the domains, because the circle in COMSOL have 4 boundaries, so that i have everytime to look witch boundaries i have to choose for the conductors.
Regards
thanks edgar.
i know that dosn´t make a difference. i asked because i am working with Matlab Livelink. so it is more practical for me to use the domains, because the circle in COMSOL have 4 boundaries, so that i have everytime to look witch boundaries i have to choose for the conductors.
Regards
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Posted:
1 decade ago
09.11.2011, 11:27 GMT-5
Terry,
yes I see, I also would like to have an option to select all boundaries on a domain automatically some way.
Cheers
Edgar
Terry,
yes I see, I also would like to have an option to select all boundaries on a domain automatically some way.
Cheers
Edgar
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Posted:
1 decade ago
09.11.2011, 11:33 GMT-5
Then you could use the function mphgetadj(...) that is part of Comsol's Matlab interface. It returns a list of the adjacent boundaries for a given domain, relieving you of the burden to look up these pesky numbers on your own.
Comsol's GUI, by the way, as of version 4.2 provides a similar feature with "Adjacent" selections.
Then you could use the function mphgetadj(...) that is part of Comsol's Matlab interface. It returns a list of the adjacent boundaries for a given domain, relieving you of the burden to look up these pesky numbers on your own.
Comsol's GUI, by the way, as of version 4.2 provides a similar feature with "Adjacent" selections.
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Posted:
1 decade ago
13.11.2011, 09:20 GMT-5
In AC/DC, I'm having sort of a similar problem, except for a different reason:
In various ACDC physics, one can only place a boundary terminal/ground as a part of the insulation - as an overriding option to the electric insulation. However, not always I want the current to go that way; I want to have potential on a specific place, and I can't do that. I figured using initial conditions for domains, but that would cause a time-dependent model, since eventually the potential will even out. I want a terminal and a ground, in MEF for example. is there a way to do this?
thanks.
In AC/DC, I'm having sort of a similar problem, except for a different reason:
In various ACDC physics, one can only place a boundary terminal/ground as a part of the insulation - as an overriding option to the electric insulation. However, not always I want the current to go that way; I want to have potential on a specific place, and I can't do that. I figured using initial conditions for domains, but that would cause a time-dependent model, since eventually the potential will even out. I want a terminal and a ground, in MEF for example. is there a way to do this?
thanks.
Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
1 decade ago
13.11.2011, 14:58 GMT-5
Hi
but in MEF: you solve for the scalar V and the vector A.
So how can you simulate a model (physicslly correct I mean) if you have the spontaneous appearance of a current (or voltage hence current via the resistance) source in the midle of your geometry, as for a port ?
For me, you need the complete, closed current loop to solve correctly A and link to V.
Therefore in EM (different from only ES or EC) one should think closed current loops, and vacuum or material volume to close the B-H fields
I'm not sure how to represent that with a "port" EM
--
Good luck
Ivar
Hi
but in MEF: you solve for the scalar V and the vector A.
So how can you simulate a model (physicslly correct I mean) if you have the spontaneous appearance of a current (or voltage hence current via the resistance) source in the midle of your geometry, as for a port ?
For me, you need the complete, closed current loop to solve correctly A and link to V.
Therefore in EM (different from only ES or EC) one should think closed current loops, and vacuum or material volume to close the B-H fields
I'm not sure how to represent that with a "port" EM
--
Good luck
Ivar