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about defining Y in reference frame
Posted 18.01.2011, 03:22 GMT-5 Chemical Reaction Engineering, Studies & Solvers Version 3.5a 1 Reply
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Hi
From the equation ,(in the cavity) V(t0) = -0.01+0.02*Y/5e-2[m]
Is Y the reference coordinate?
Can I define Y if i'd like to limit solving Y at 5e-6[m] instead of time range?
Thank you very much for your help
--
Pardon for my bad english
From the equation ,(in the cavity) V(t0) = -0.01+0.02*Y/5e-2[m]
Is Y the reference coordinate?
Can I define Y if i'd like to limit solving Y at 5e-6[m] instead of time range?
Thank you very much for your help
--
Pardon for my bad english
1 Reply Last Post 18.01.2011, 06:06 GMT-5
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Posted:
1 decade ago
Hi
if you are in 2D or 3D norally y an Y are the 2nd space coordinate (one for the reference frame one for the spatial frame (or the opposite I never get it right pls check carefully, it has its importance. Note also that between 3.5 and 4 there are chnges in the default behaviour (and names) of the frames.
finally in 3.5 take some care with units and fractions, if I remember right 1/x[m] is NOT the same as 1/(x[m]) but pls cross check
--
Good luck
Ivar
if you are in 2D or 3D norally y an Y are the 2nd space coordinate (one for the reference frame one for the spatial frame (or the opposite I never get it right pls check carefully, it has its importance. Note also that between 3.5 and 4 there are chnges in the default behaviour (and names) of the frames.
finally in 3.5 take some care with units and fractions, if I remember right 1/x[m] is NOT the same as 1/(x[m]) but pls cross check
--
Good luck
Ivar